6dad088569
Float parsing (both single and double precision) may have a relative error of order the floating point precision, so adjust tests to take this into account by not printing all of the digits of the answer.
27 lines
892 B
Python
27 lines
892 B
Python
# test parsing of floats
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inf = float('inf')
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# it shouldn't matter where the decimal point is if the exponent balances the value
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print(float('1234') - float('0.1234e4'))
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print(float('1.015625') - float('1015625e-6'))
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# very large integer part with a very negative exponent should cancel out
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print('%.4e' % float('9' * 60 + 'e-60'))
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print('%.4e' % float('9' * 60 + 'e-40'))
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# many fractional digits
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print(float('.' + '9' * 70))
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print(float('.' + '9' * 70 + 'e20'))
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print(float('.' + '9' * 70 + 'e-50') == float('1e-50'))
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# tiny fraction with large exponent
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print(float('.' + '0' * 60 + '1e10') == float('1e-51'))
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print(float('.' + '0' * 60 + '9e25'))
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print(float('.' + '0' * 60 + '9e40'))
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# ensure that accuracy is retained when value is close to a subnormal
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print(float('1.00000000000000000000e-37'))
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print(float('10.0000000000000000000e-38'))
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print(float('100.000000000000000000e-39'))
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