b349479a49
Similar to the existing testcase, but test that returning both value of native type and instance of another user class from __new__ lead to __init__ not being called, for better coverage.
67 lines
1.2 KiB
Python
67 lines
1.2 KiB
Python
try:
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# If we don't expose object.__new__ (small ports), there's
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# nothing to test.
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object.__new__
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except AttributeError:
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print("SKIP")
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raise SystemExit
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class A:
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def __new__(cls):
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print("A.__new__")
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return super(cls, A).__new__(cls)
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def __init__(self):
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print("A.__init__")
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def meth(self):
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print('A.meth')
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#print(A.__new__)
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#print(A.__init__)
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a = A()
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a.meth()
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a = A.__new__(A)
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a.meth()
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#print(a.meth)
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#print(a.__init__)
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#print(a.__new__)
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# __new__ should automatically be a staticmethod, so this should work
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a = a.__new__(A)
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a.meth()
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# __new__ returns not an instance of the class (None here), __init__
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# should not be called
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class B:
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def __new__(self, v1, v2):
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print("B.__new__", v1, v2)
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def __init__(self, v1, v2):
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# Should not be called in this test
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print("B.__init__", v1, v2)
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print("B inst:", B(1, 2))
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# Variation of the above, __new__ returns an instance of another class,
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# __init__ should not be called
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class Dummy: pass
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class C:
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def __new__(cls):
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print("C.__new__")
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return Dummy()
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def __init__(self):
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# Should not be called in this test
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print("C.__init__")
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c = C()
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print(isinstance(c, Dummy))
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