2827d62e8b
Implements 'def f(*, a)' and 'def f(*a, b)', but not default keyword-only args, eg 'def f(*, a=1)'. Partially addresses issue #524.
69 lines
906 B
Python
69 lines
906 B
Python
# to test keyword-only arguments
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# simplest case
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def f(*, a):
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print(a)
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f(a=1)
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# with 2 keyword-only args
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def f(*, a, b):
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print(a, b)
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f(a=1, b=2)
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f(b=1, a=2)
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# positional followed by bare star
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def f(a, *, b, c):
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print(a, b, c)
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f(1, b=3, c=4)
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f(1, c=3, b=4)
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f(1, **{'b':'3', 'c':4})
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try:
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f(1)
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except TypeError:
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print("TypeError")
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try:
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f(1, b=2)
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except TypeError:
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print("TypeError")
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try:
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f(1, c=2)
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except TypeError:
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print("TypeError")
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# with **kw
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def f(a, *, b, **kw):
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print(a, b, kw)
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f(1, b=2)
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f(1, b=2, c=3)
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## with a default value; not currently working
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#def g(a, *, b=2, c):
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# print(a, b, c)
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#
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#g(1, c=3)
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#g(1, b=3, c=4)
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#g(1, **{'c':3})
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#g(1, **{'b':'3', 'c':4})
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# with named star
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def f(*a, b, c):
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print(a, b, c)
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f(b=1, c=2)
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f(c=1, b=2)
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# with positional and named star
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def f(a, *b, c):
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print(a, b, c)
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f(1, c=2)
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f(1, 2, c=3)
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f(a=1, c=3)
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