docs/reference/isr_rules.rst: Describe uasyncio-IRQ interface.

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Peter Hinch 2022-01-30 16:37:42 +00:00 committed by Damien George
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commit 80b81acea5

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@ -219,6 +219,33 @@ Exceptions
If an ISR raises an exception it will not propagate to the main loop. The interrupt will be disabled unless the If an ISR raises an exception it will not propagate to the main loop. The interrupt will be disabled unless the
exception is handled by the ISR code. exception is handled by the ISR code.
Interfacing to uasyncio
-----------------------
When an ISR runs it can preempt the `uasyncio` scheduler. If the ISR performs a `uasyncio`
operation the scheduler's operation can be disrupted. This applies whether the interrupt is hard
or soft and also applies if the ISR has passed execution to another function via
`micropython.schedule`. In particular creating or cancelling tasks is invalid in an ISR context.
The safe way to interact with `uasyncio` is to implement a coroutine with synchronisation performed by
`uasyncio.ThreadSafeFlag`. The following fragment illustrates the creation of a task in response
to an interrupt:
.. code:: python
tsf = uasyncio.ThreadSafeFlag()
def isr(_): # Interrupt handler
tsf.set()
async def foo():
while True:
await tsf.wait()
uasyncio.create_task(bar())
In this example there will be a variable amount of latency between the execution of the ISR and the execution
of ``foo()``. This is inherent to cooperative scheduling. The maximum latency is application
and platform dependent but may typically be measured in tens of ms.
General issues General issues
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