py/parse: Remove unnecessary check in const folding for ** operator.

In this part of the code there is no way to get the ** operator, so no need
to check for it.

This commit also adds tests for this, and other related, invalid const
operations.
This commit is contained in:
Damien George 2020-04-06 12:19:03 +10:00
parent a5f2ae10fe
commit 4914731e58
3 changed files with 18 additions and 2 deletions

View File

@ -655,8 +655,8 @@ STATIC bool fold_constants(parser_t *parser, uint8_t rule_id, size_t num_args) {
return false; return false;
} }
mp_token_kind_t tok = MP_PARSE_NODE_LEAF_ARG(peek_result(parser, i)); mp_token_kind_t tok = MP_PARSE_NODE_LEAF_ARG(peek_result(parser, i));
if (tok == MP_TOKEN_OP_AT || tok == MP_TOKEN_OP_SLASH || tok == MP_TOKEN_OP_DBL_STAR) { if (tok == MP_TOKEN_OP_AT || tok == MP_TOKEN_OP_SLASH) {
// Can't fold @ or / or ** // Can't fold @ or /
return false; return false;
} }
mp_binary_op_t op = MP_BINARY_OP_LSHIFT + (tok - MP_TOKEN_OP_DBL_LESS); mp_binary_op_t op = MP_BINARY_OP_LSHIFT + (tok - MP_TOKEN_OP_DBL_LESS);

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@ -15,3 +15,12 @@ test_syntax("a = const(x)")
# redefined constant # redefined constant
test_syntax("A = const(1); A = const(2)") test_syntax("A = const(1); A = const(2)")
# these operations are not supported within const
test_syntax("A = const(1 @ 2)")
test_syntax("A = const(1 / 2)")
test_syntax("A = const(1 ** 2)")
test_syntax("A = const(1 << -2)")
test_syntax("A = const(1 >> -2)")
test_syntax("A = const(1 % 0)")
test_syntax("A = const(1 // 0)")

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@ -1,2 +1,9 @@
SyntaxError SyntaxError
SyntaxError SyntaxError
SyntaxError
SyntaxError
SyntaxError
SyntaxError
SyntaxError
SyntaxError
SyntaxError